Molar mass of BaCrO4,
MM = 1*MM(Ba) + 1*MM(Cr) + 4*MM(O)
= 1*137.3 + 1*52.0 + 4*16.0
= 253.3 g/mol
Molar mass of BaCrO4= 253.3 g/mol
s = 3.7*10^-3 g/L
To covert it to mol/L, divide it by molar mass
s = 3.7*10^-3 g/L / 253.3 g/mol
s = 1.461*10^-5 mol/L
At equilibrium:
BaCrO4 <----> Ba2+ + CrO42-
s s
Ksp = [Ba2+][CrO42-]
Ksp = (s)*(s)
Ksp = 1(s)^2
Ksp = 1(1.461*10^-5)^2
Ksp = 2.134*10^-10
Answer: 2.1*10^-10
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