Here ,for changing 12degree F to C
T(C)/100 = (12 - 32)/180
T(C) = -11.1 degree C
change in temperature in degree C = 120 - (-11.1)
change in temperature in degree C = 131.1 degree C
change in temperature in degree C = change in temperature in K
change in temperature in K = 131.1 K
the change in temperature is 131.1 K
How will you solve What is the change in temperature from 127F to 120rCin kalvin?
What kind of limits when you use Log-mean temperature difference method? How do I solve this when LMTD=and what situation like this?(5 % ) ATym ATA-4T &Ta LATDn
What kind of limits when you use Log-mean temperature difference method? How do I solve this when LMTD=and what situation like this?(5 % ) ATym ATA-4T &Ta LATDn
solve
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II. Probabilities From the section above, you should...
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