Question

ㅃ cnoner 3-2010 Sprint × ed oumy.ecuweba g to the Favontes Bar folder, Or import from another browser. Import favorites Home Chapter 3 d P(A). PLE) P(F). d P(N). d P(O) ind P(S) 8. What is the probability of drawing a red card in a standard deck of 52 cards? 19. What is the probability of drawing a club in a standard deck of 52 cards? 20. What is the probability of rolling an even number of dots with a fair, six-sided die numbered one through six? 21. What is the probability of rolling a prime number of dots with a fair, six-sided die numbered one through six? Use the following information to answer the next two exercises You see a game at a local fair. You have to throw a dart at a color wheel. Each section on the color wheel is equal in area.

Answer 1

Answer 18. Total number of red cards in the standard deck of 52 cards = 26.

Probability of drawing a red card from the standard deck of 52 cards

$\begin{gathered} = \frac{{{\text{Total number of red cards}}}}{{{\text{Total number of cards}}}} \hfill \\ = \frac{{26}}{{52}} \hfill \\ = \frac{1}{2}({\text{or 0}}{\text{.5)}} \hfill \\ \end{gathered}$

Answer 19. Total number of cards from suit club in the standard deck of 52 cards = 13.

Probability of drawing a club from the standard deck of 52 cards

$\begin{gathered} = \frac{{{\text{Total number of club cards}}}}{{{\text{Total number of cards}}}} \hfill \\ = \frac{{13}}{{52}} \hfill \\ = \frac{1}{4}({\text{or 0}}{\text{.25)}} \hfill \\ \end{gathered}$

Answer 20. On rolling a fair six-sided die, number of possible outcomes with even number of dots(2, 4, 6) = 3.

Probability of rolling an even number of dots with a fair six-sided die

$\begin{gathered} = \frac{{{\text{Number of possible outcomes}}}}{{{\text{Total number of outcomes}}}} \hfill \\ = \frac{3}{6} \hfill \\ = \frac{1}{2}({\text{or 0}}{\text{.5)}} \hfill \\ \end{gathered}$

Answer 21. On rolling a fair six-sided die, number of possible outcomes with prime number of dots(2, 3, 5) = 3.

Probability of rolling prime number of dots with a fair six-sided die

$\begin{gathered} = \frac{{{\text{Number of possible outcomes}}}}{{{\text{Total number of outcomes}}}} \hfill \\ = \frac{3}{6} \hfill \\ = \frac{1}{2}({\text{or 0}}{\text{.5)}} \hfill \\ \end{gathered}$