2) How much lithium metal is needed to reaction with 15.0g of CH3CH2I using a 15%...

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2) How much lithium metal is needed to reaction with 15.0g of CH3CH2I using a 15% excess of lithium to make methyllithium? Th

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CH₃ CH₂ I +2 Li LCH₂ CH₃ + LiI М. 4 сну си, і том moler mass 15.og 155.97 g/mol 0.0962 mol 2x0.0962 roles of Li require: (isl

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2) How much lithium metal is needed to reaction with 15.0g of CH3CH2I using a 15%...

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Add Answer to: 2) How much lithium metal is needed to reaction with 15.0g of CH3CH2I using a 15%...

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