Question

1.1: E&M Proportional Reasoning Two charge objects are a certain distance Rant. The electrostatic force between there is 2.010-2N Asuming they can be treated point charges, we proportional soning to calculate what the force becomes when the distance between them is halvoil, one of the charges in double and the other charge is triple 1.2: Proportional Reasoning in an Unfamiliar Circumstance The heat capacity of a Debye solid is given by C=B12 Where Bois Dee's constant and is the temperature, The specific heat of Copper at a particular temperature is 5 Cal/deg. If I triple the temperature, use proportional reasoning to find the new capacity? 2.1: Unit check 1 Does this question pass a unit check? Show me why or why not, mm Q. RO 2.2: Unit check 2 Does this equation pass a unit check! Show me why or why not, 3.1: Draw a diagram Draw a fully labeled dingram to illustrate the following problem: Two point charges all are at x0 and x L respectively, and free to mo. Athird charge is placed so that the entire three-charge system is in static equilibrium. What is the magnitude of the third charge?

Answer 1

Aus II r2 F = 2x10m2 N =Kq V2 - Now, the r = r , q = 291 , 42 = 392 ,. F = kq' q = F = K (2q, ) (392) = F = 24 kq, q2 Shut kq 19 =F2 -) E =24 F -) F'=24X2X162 Newtons ! L = F = 486102 Newtons = 0.48 Newtons Answel Ask- po = Bp 12 TS T3 quitially at temps. t , C; = 5 Call degree . When I = 3T; then C = Bp 12 T3 ( 3 Tc ) ² = 9 / 127 37 ) G = 96= 45 cal/dag. 5 Ansuel

Aus 2011 yes, this equation pass unit checks - because on LHS we have charge which haves unit of Coulomb. Unit of G=Nm 2 unit of k= Nm? Exkg kg Q = Gmima units of m, and me KQZ [a] = [G] [mi] [m2] [K][Q] cb = N-m² to Kga Nm xe [LHS cb=1 = (6= [RHS] Ans2.a | No, this equation do not pass whit check. on LHS we have charge Unit of LH S=Cb-containks IN-m² RHS = 1 = VT = unit less - trz INm2 c2 c2 Hence the RHS is unitless whereas LHS has the unit of charge, hence this equation is not correct.