use:
pH = -log [H+]
2.8 = -log [H+]
[H+] = 1.585*10^-3 M
use:
pH = -log [H+]
6.25 = -log [H+]
[H+] = 5.623*10^-7 M
Decrease in concentration of [H+] = 1.585*10^-3 M - 5.623*10^-7 M
= 1.58*10^-3 M
Since solution volume is 1 L,
Mol of H+ decreased = 1.58*10^-3 mol
So,
Mol of OH- added = 1.58*10^-3 mol
Answer: B
A4 Which ONE of the following solids when added to 1 L of water will change...
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