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In Class Exercise - The Gibbs Free Energy Change, AG 1) Determining the Standard Gibbs Free Energy Change (AGⓇ) for a Chemica
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u Att reaxen = Hrvenkul [ Product Ato - Learfaut A Ho] +1XH H2oy ). = 1 BAtcong + 224 *ww.f) – (1x11 coche) zwy + 1** Cx-roueAus altonen - TAS = t191.22 98 K X355-64 Molk. = +131.23 th - 208 * 355-64 = +15122 RT - 10598017 1701 101 1000 = 1 mol MOJ =T= 0.5376x10 5/mor __wrop So, T = 53706 Kelvin more than T=537.6k Reaction sontandus. T= 538 ik. Indages & T= 538-27315 18 =

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