Question

7-14 help

7) What is the final concentration when 30gms of code dissolved in 2 tters of solution ofion when 30gms of codeine phosphate is 8) Ifa kg of an ointment contains 350gms of active ingredient, what is the percentage strength of the ointments 911 75 gms of codeine phosphate are dissolved in 3 iters of sterile water. what is the resultant ratio strength of the solution 10) A drug label states that the addito ug label states that the addition of Bml of soline will result in a drug centration of 250mg/ml. You realized that you just added 13ml to the val. What is the final concentration in the via

Answer 1

7 No. of moles of codenine phosphate = molot = 30 397.49 = 0.0755 moles - ASF conc. of codenine phosphate = No. of motes volume of soin in lime. = 0.0755 = 0.0377 M conc. of zomg codenine phosphate in al water is 0.0377 M (8 1kg oinaments =350g active ingredient. 1000g oinaments = 350 g active ingredient. 100g oinament = xe a active reagent. : = 350XICO ze= 350 :- percent strength of oinament = 35%. 6 . 75gm codenine phosphate in 3 mm eitre. regm of codenine phosphate - 1 litre. x = 75 - 25gét strength of son is as gel 3

10 ] 8 me saline soln - 250 mglme. :. 13 me saline soin = n mglme. ve 250x13 - 406.25 mgime. . The final conc. of vial = 406.25 mglne. 250e dcetic acid ip 100ml -25l. x the tretie acrt natamenty 117 ime acetic acid in 100 me = 1% - 25 me acetic acid in 100 me = 251 i 25*2.5 me acetic acid in 250me=257. : 62.5 me acetic acid in 250 me=25%. For 257 250 me acetic acid 62.5 me acetic acid is needed. . 13 I 1 147 . soo me soin contain o. s g . . loo me soin contain oilg. b ig lo me soin is. i 0.19 contain in low me soin 0.17. percent strength of soln is oolt. 1 pound = 0.454 KI. :-125 pound= 56.75kg :. 5 mg = 1 kg :x=283.75 mg : x mq = 56.75kg 250 125 pound patient need 283.75 mg drug. : x= 56.7sxs I