Question

what Celsius temperature is required to increase the volume of a sealed balloon from 2.0 L to 3.0 L if the initial temperature is 15°C and the atmospheric pressure is constant?

Answer 1

Solution

We know that Charles law states that, at a constant pressure the volume of an ideal gas is proportional to the temperature.

V $\alpha$ T

V = kT

V/T = k

So,

V₁/T₁ = V₂/_{​​​​​​}T₂

Where, V₁ = 2.0 L, V₂ = 3.0 L, T₁ = 15°C = 288. 15 K, T₂ = ?

Putting these values in the above equation then we get

2.0 L/288.15 K = 3.0 L/T₂

T₂ = 288.15 × 3.0 L/ 2.0

T₂ = 432.225 K = 159.075°C

159.075°C temperature is required to increase the volume of a sealed balloon from 2.0 L to 3.0 L.