Calculate the pH of an aqueous solution of sodium hydrogen phosphite, NaHPO3.
For phosphorous acid, H2PO3,
pKa'= 2.00 and pKa″
= 6.59.
Dissociation of H2PO3 in water takes place in two steps.
1. H2PO3 (aq) + H2O
(l)
H3O + (aq) + HPO3- (aq)
pKa ' = 2.00
2. HPO3- (aq) + H2O
(l)
H3O + (aq) + PO32- (aq)
pKa " = 6.59
From above reactions, it is clear that HPO3- is an intermediate form of H2PO3 and PO32-.
We know that, pH of intermediate form of diprotic acid is calculated by using formula pH = 1/2 ( pK 1 + pK 2)
pH of aqueous solution of NaHPO3 = 1/2
( pKa ' + pKa " )
= 1/2 ( 2.00 + 6.59 )
= 1/2 ( 8.59 )
= 4.295
= 4.30
ANSWER : pH of aqueous solution of NaHPO3 =4.30
Calculate the pH of an aqueous solution of sodium hydrogen phosphite, NaHPO3. For phosphorous acid, H2PO3,...
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