Question

QUESTION 1 How much work (in Joules) needs to done on an ideal gas to increase its volume from 1 L to 5 L at a constant pressure of 1 ATM?

Answer 1

Given:-

• Initial volume of the gas :
  Vi=12
  
• Final volume of the gas :
  V=5L
  
• Constant pressure         :
  P=1 atm
  

We know that,

1000 = 71
   and
1 atm = 1011325 Pa

Therefore,

• 
  Vi=1 L= 0.001 m
  
• 
  V2 = 5 L= 0.005 m
  
• 
  P=1 atm = 101325 Pa
  

Work done on the gas is given by,

W = -PAV

W = -P(V2-V1)

W = –101325 x (0.005 -0.001)

W = -405.3

This is the work done (in Joules) needs to be done on an ideal gas. Negative sign indicates that the work is done on the gas.