1)
Given:
T = 26.0 oC
=(26.0+273)K
= 299.0 K
A = 4.4*10^12 L.mol-1.s-1
Ea = 64.0 KJ/mol
= 64000.0 J/mol
R = 8.314 J/mol.K
use:
K = A*e^(-Ea/RT)
= 4.4*10^12*e^(-64000.0/(8.314*299.0))
= 4.4*10^12*e^(-25.7453)
= 4.4*10^12*6.591*10^-12
= 29.0 L.mol-1.s-1
Answer: 29.0 L.mol-1.s-1
2)
Given:
T1 = 352 K
T2 = 426 K
K1 = 109 L.mol-1.s-1
K2 = 185 L.mol-1.s-1
use:
ln(K2/K1) = (Ea/R)*(1/T1 - 1/T2)
ln(185/109) = ( Ea/8.314)*(1/352 - 1/426)
0.529 = (Ea/8.314)*(4.935*10^-4)
Ea = 8912 J/mol
Ea = 8.91 KJ/mol
Answer: 8.91 KJ/mol
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