Question

I need ALL answers #1-6

please!!!!

College Physics 1 - Homework L Questions F 1. Two objects moving horizontally on a frictionless surface at the same initial speed collide and stick together as shown to the right. Object 1 is less massive than object 2. Which of the five post- collision paths are possible for this combined mass? Explain. 2. A turntable is rotating at 45 rpm when the power is turned off. If it rotates through 45° as it uniformly comes to rest, determine its angular acceleration. 3. Consider a carousel 32 feet in diameter. This carousel takes 11 s to accelerate from rest to its operating speed of 3.25 rev/min. During this time, find a) its angular acceleration and b) the number of revolutions made. Now, consider a horse 4 feet from the edge of this carousel. Determine its c) maximum speed, d) maximum centripetal acceleration, and e) tangential acceleration. 4. Consider the Earth as it rotates daily on its axis. Give it's a) angular speed and b) angular acceleration. Determine the speed with respect to the Earth's center of a person standing on c) the south pole and d) the equator. 5. Which has more rotational inertia; a bowling ball or a volleyball? Explain. 6. A 0.125 kg meter stick is rotating (as shown to the right) in a horizontal plane about an axis through its center at 3.45 rad/s. a) Find the rotational inertia of this stick. At one of its ends, find its b) speed and c) centripetal acceleration. If this stick comes to rest in 4.27 s, find d) its angular acceleration and e) the net torque acting on it.

Answer 1

(1) Pi= m. v..] + ma vai Pj = (m, tha) . Pj = Pi vt coming tong) Voģ+ m2 mit me " tano= Coeft of i Coep yî Since m, 2 m2 tana 2 acurº But possible path i B 957bm= 0.75065., W.-297-4071 radll. Q = 45 = 0.785 rad., W=0 . w2w. 2 = 220 do ( 47112 19.13 gadle2 20.7 L = 14-13 rad| 82 3) V- 3.25 per min 0.0542 gbe , w=2005 0.34 radlso w=o+ht koo R = 0.34 = 0.031 radls2) (3) @= ,4+2= 4 0.03141213 16872 rod. - n = 0 = 0.298 / ono of revans. (C) r=484 = 1022m max= vw=0.415 mle. (d) Tac = W27 = 0.1417122 (e) Tap = 72 = 0.038 m|12)

(5) The bowling ball Let w be ang speed of Earth rotation, eva la a) At South pole, V=0 13 At equefor, V=Rw I The bowling ball would have moet inertia because it has most mass. more massive an object, the more resistance it has against outside forces. 6) Me 0.125 kg, W = 3.45 radls. @ I = L M12 - LX0:125x1= 0.0104 kg m 2 O v= ļw = 0.5*3:45= 1.725 ml. (c) aca werg% = Regte mso 5.951 m/s2 W-3.45 nodls. t-4,270. C Bu da W700808 gadle? (e) P= Id = 0.0104*0.808 = 8.403x10-3 Nm