1. What is the value of the following call option according to the Black Scholes Option Pricing Model? What is the value of the put options?
Stock Price = $42.50
Strike Price = $45.00
Time to Expiration = 3 Months = 0.25 years.
Risk-Free Rate = 3.0%.
Stock Return Standard Deviation = 0.45.
As per Black Scholes Model | ||||||
Value of call option = (S)*N(d1)-N(d2)*K*e^(-r*t) | ||||||
Where | ||||||
S = Current price = | 42.5 | |||||
t = time to expiry = | 0.25 | |||||
K = Strike price = | 45 | |||||
r = Risk free rate = | 3.0% | |||||
q = Dividend Yield = | 0% | |||||
σ = Std dev = | 45% | |||||
d1 = (ln(S/K)+(r-q+σ^2/2)*t)/(σ*t^(1/2) | ||||||
d1 = (ln(42.5/45)+(0.03-0+0.45^2/2)*0.25)/(0.45*0.25^(1/2)) | ||||||
d1 = -0.108204 | ||||||
d2 = d1-σ*t^(1/2) | ||||||
d2 =-0.108204-0.45*0.25^(1/2) | ||||||
d2 = -0.333204 | ||||||
N(d1) = Cumulative standard normal dist. of d1 | ||||||
N(d1) =0.456917 | ||||||
N(d2) = Cumulative standard normal dist. of d2 | ||||||
N(d2) =0.36949 | ||||||
Value of call= 42.5*0.456917-0.36949*45*e^(-0.03*0.25) | ||||||
Value of call= 2.92 |
As per Black Scholes Model | ||||||
Value of put option = N(-d2)*K*e^(-r*t)-(S)*N(-d1) | ||||||
Where | ||||||
S = Current price = | 42.5 | |||||
t = time to expiry = | 0.25 | |||||
K = Strike price = | 45 | |||||
r = Risk free rate = | 3.0% | |||||
q = Dividend Yield = | 0% | |||||
σ = Std dev = | 45% | |||||
d1 = (ln(S/K)+(r-q+σ^2/2)*t)/(σ*t^(1/2) | ||||||
d1 = (ln(42.5/45)+(0.03-0+0.45^2/2)*0.25)/(0.45*0.25^(1/2)) | ||||||
d1 = -0.108204 | ||||||
d2 = d1-σ*t^(1/2) | ||||||
d2 =-0.108204-0.45*0.25^(1/2) | ||||||
d2 = -0.333204 | ||||||
N(-d1) = Cumulative standard normal dist. of -d1 | ||||||
N(-d1) =0.543083 | ||||||
N(-d2) = Cumulative standard normal dist. of -d2 | ||||||
N(-d2) =0.63051 | ||||||
Value of put= 0.63051*45*e^(-0.03*0.25)-42.5*0.543083 | ||||||
Value of put= 5.08 |
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