13.38 Given the same reactant concentrations, the reaction CO(g) + Cl2(g) — COC12(8) at 250°C is...
Enter your answer in the provided box. Given the same reactant concentrations, the reaction CO(g) + Cl2(g) COCl2() at 235°C is 54.3 times as fast as the same reaction at 157°C. Calculate the activation energy for this reaction. Assume that the frequency factor is constant. kJ/mol
Given the same reactant concentrations, the reaction CO(g) + Cl_2(g) rightarrow COCl_2(g) at 263 degree C is 219 times as fast as the same reaction at 153 degree C. Calculate the activation energy for this reaction. Assume that the frequency factor is constant.
please show all steps. The decomposition reaction of COC12 is, COCldg,-CO(g) + Cl2(g) Kc = 2.2 × 10-10. The initial concentration of CoCl is 0.3166 M 3. the (a) At equilibrium, the concentrations of the products are concentration of reactant. (A) greater than (B) less than (D) unknown because more information is needed to determine. (C) equal to (b) Fill the ICE table below COC: Ico Initial concentration (M) Changes (M) Equilibrium concentration (M) -x (c) Calculate the equilibrium concentration...
A student ran the following reaction in the laboratory at 541 K: COC12(E) CO(g) + Cl2(g) When she introduced 1.13 moles of COC12(e) into a 1.00 liter container, she found the equilibrium concentration of Cl2(g) to be 3.83x10-2 M. Calculate the equilibrium constant, K, she obtained for this reaction.
The equilibrium constant, Kc. for the following reaction is 1.29×102 at 600 K. COC12(g) = CO(g) + Ch(g) Calculate the equilibrium concentrations of reactant and products when 0.305 moles of COCL() are introduced into a 1.00 L vessel a 600 K CoC] Co]
Consider the following reaction: COCl2(g) = CO(g) + Cl2(8) A reaction mixture initially contains 1.6 M COC12. Determine the equilibrium concentrations of COCI, CO, and Cl2 if Kc for the reaction at this temperature is 8.33 x 10-4. Calculate this based on the assumption that the answer is negligible compared to 1.6. Use x is small approximation. Show Q Validity check [Cl2] = [CO]= [COCI2] = Calculate the reaction quotient, Q A % Validity Check A Calculate the A/ equilibrium...
The equilibrium constant, K, for the following reaction is 2.52x10-2 at 620 K. COC12(g) * CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 10.5 L container at 620 K contains 0.264 M COCl2, 8.15x10-2 M CO and 8.15x10-2 M Cl. What will be the concentrations of the three gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 4.32 L? M [COCl2] = [CO] = [Cl2] =...
Question 26 6 pts 26. Consider the following chemical reaction: CO(g) + Cl2(8) -------------> COC12 (8) At the beginning 0.400 M CO(g) is mixed with 0.0500 M Cl2(g). At equilibrium, 0.0100 M of the product is produced. Calculate the equilibrium constant. OK -8.81 K-1.20 x 10exp-5 K=0.641 OK = 1.99x 10exp-3 Question 27 6 pts 27. Consider the following chemical reaction: N2(g) + 202(8) 2NO2(g) decreasing the pressure of reaction mixture will decrease amounts of O2(g) increase amounts of NO2(g)...
The equilibrium constant, K, for the following reaction is 2.36x102 at 618 K. COC12(8) CO(g) + Cl2() An equilibrium mixture of the three gases in a 7.22 L container at 618 K contains 0.352 M COCI, 9.11x102 M CO and 9.11 102 M CI. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 15.0 L? [COCI, - [CO] (C12] - Submit Answer Retry Entire Group 9...
The equilibrium constant, Kc, for the following reaction is 77.5 at 600 K. CO(g) + Cl2(g) COCl2(g) Calculate the equilibrium concentrations of reactant and products when 0.325 moles of CO and 0.325 moles of Cl2 are introduced into a 1.00 L vessel at 600 K. [CO] = M [Cl2] = M [COCl2] = M