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![] 2 o initial cone at eas [COI2] = 0-352M ,[co] = (CI2] = 90118162 = 0.091 m malarity a volume volume is increased from 7-222](http://img.homeworklib.com/questions/58a86110-af7d-11eb-b616-3d2c1f0db3e1.png?x-oss-process=image/resize,w_560)
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The equilibrium constant, K, for the following reaction is 2.36x102 at 618 K. COC12(8) CO(g) +...
The equilibrium constant, K, for the following reaction is 2.36x10-2 at 618 K. COCI,(E)=CO(g) +C1, An...
The equilibrium constant, K, for the following reaction is 2.36x10-2 at 618 K. COCI,(E)=CO(g) +C1, An equilibrium mixture of the three gases in a 10.4 L container at 618 K contains 0.361 M COCI, 9.23x10-2M CO and 9.23 102 M CI. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 17.8 L? [COCI,] = [CO] = [CI] -
please solve The equilibrium constant, K, for the following reaction is 4.85x10-2 at 641 K. COC12(8)...
please solve
The equilibrium constant, K, for the following reaction is 4.85x10-2 at 641 K. COC12(8) CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 6.59 L container at 641 K contains 0.205 M COCI, 9.98x102 M CO and 9.98*10-M CI2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 15.5 L? [COCI2] = [CO] [Cl] Submit Answer
The equilibrium constant, K, for the following reaction is 2.52x10-2 at 620 K. COC12(g) * CO(g)...
The equilibrium constant, K, for the following reaction is 2.52x10-2 at 620 K. COC12(g) * CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 10.5 L container at 620 K contains 0.264 M COCl2, 8.15x10-2 M CO and 8.15x10-2 M Cl. What will be the concentrations of the three gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 4.32 L? M [COCl2] = [CO] = [Cl2] =...
The equilibrium constant, K, for the following reaction is 1.29 102 at 600 K COC2(g)CO+Cl2(8) An...
The equilibrium constant, K, for the following reaction is 1.29 102 at 600 K COC2(g)CO+Cl2(8) An equilibrium mixture of the three gases in a 1 00 L flask at 600 K contains 0.178 М СОС, 47910-3 M CO and 4.79102 M Clh What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.75 102 mol of 10 Mco and 4.79x102 Ca is added to the flask? [cocil- Submit Answer Retry Entire Group 4 more group...
6) Distrubuting Equilibrium a) The equilibrium constant, K, for the following reaction is 10.5 at...
6) Distrubuting Equilibrium a) The equilibrium constant, K, for the following reaction is 10.5 at 350 K 2CH2Cl2(g)CH4(g + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.32x10-2 M CH2C2, 0.172 M CH4 and 0.172 M CCI4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 9.58x102 mol of CH4(g is added to the flask? CH2Cl2l [CH4 [CCI4] b) The equilibrium constant, K, for the...
he equilibrium constant, K, for the following reaction is 1.53×10-2 at 605 K. COCl2(g) CO(g) +...
he equilibrium constant, K, for the following reaction is 1.53×10-2 at 605 K. COCl2(g) CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 8.38 L container at 605 K contains 0.288 M COCl2, 6.63×10-2 M CO and 6.63×10-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 14.5 L? [COCl2] = _______ M [CO] =_________ M [Cl2] =________ M
The equilibrium constant, K, for the following reaction is 2.02x10 at 513 K. PC13(g) = PCH(g)...
The equilibrium constant, K, for the following reaction is 2.02x10 at 513 K. PC13(g) = PCH(g) + Chz(g) An equilibrium mixture of the three gases in a 7.10 L container at 513 K contains 0.384 M PCIS, 8.81x10 - M PCI and 8.81*10M Cl. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 16.0 L? [PC1s] =D (PC13] = [Cl] Submit Answer Retry Entire Group 3...
1) The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g)...
1) The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.311 M HI, 4.18×10-2 M H2 and 4.18×10-2 M I2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 2.85×10-2 mol of I2(g) is added to the flask? 2) The equilibrium constant, K, for the following reaction is 1.20×10-2 at...
The equilibrium constant, K, for the following reaction is 1.29E-2 at 600 K. COCl2(g) <--> CO(g)...
The equilibrium constant, K, for the following reaction is 1.29E-2 at 600 K. COCl2(g) <--> CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 600 K contains 0.297 M COCl2, 6.19E-2 M CO and 6.19E-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.13E-2 mol of CO(g) is added to the flask? [COCl2] = M [CO] = M [Cl2] = M
The equilibrium constant, K, for the following reaction is 1.29×10-2 at 600 K. COCl2(g) ---> CO(g)...
The equilibrium constant, K, for the following reaction is 1.29×10-2 at 600 K. COCl2(g) ---> CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 600 K contains 0.293 M COCl2, 6.15×10-2 M CO and 6.15×10-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 5.25×10-2mol of Cl2(g) is added to the flask? [COCl2] =___? M [CO] =___? M [Cl2] =___? M
The equilibrium constant, K, for the following reaction is 2.36x10-2 at 618 K. COCI,(E)=CO(g) +C1, An equilibrium mixture of the three gases in a 10.4 L container at 618 K contains 0.361 M COCI, 9.23x10-2M CO and 9.23 102 M CI. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 17.8 L? [COCI,] = [CO] = [CI] -
please solve
The equilibrium constant, K, for the following reaction is 4.85x10-2 at 641 K. COC12(8) CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 6.59 L container at 641 K contains 0.205 M COCI, 9.98x102 M CO and 9.98*10-M CI2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 15.5 L? [COCI2] = [CO] [Cl] Submit Answer
The equilibrium constant, K, for the following reaction is 2.52x10-2 at 620 K. COC12(g) * CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 10.5 L container at 620 K contains 0.264 M COCl2, 8.15x10-2 M CO and 8.15x10-2 M Cl. What will be the concentrations of the three gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 4.32 L? M [COCl2] = [CO] = [Cl2] =...
The equilibrium constant, K, for the following reaction is 1.29 102 at 600 K COC2(g)CO+Cl2(8) An equilibrium mixture of the three gases in a 1 00 L flask at 600 K contains 0.178 М СОС, 47910-3 M CO and 4.79102 M Clh What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.75 102 mol of 10 Mco and 4.79x102 Ca is added to the flask? [cocil- Submit Answer Retry Entire Group 4 more group...
6) Distrubuting Equilibrium a) The equilibrium constant, K, for the following reaction is 10.5 at 350 K 2CH2Cl2(g)CH4(g + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.32x10-2 M CH2C2, 0.172 M CH4 and 0.172 M CCI4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 9.58x102 mol of CH4(g is added to the flask? CH2Cl2l [CH4 [CCI4] b) The equilibrium constant, K, for the...
The equilibrium constant, K, for the following reaction is 2.02x10 at 513 K. PC13(g) = PCH(g) + Chz(g) An equilibrium mixture of the three gases in a 7.10 L container at 513 K contains 0.384 M PCIS, 8.81x10 - M PCI and 8.81*10M Cl. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 16.0 L? [PC1s] =D (PC13] = [Cl] Submit Answer Retry Entire Group 3...
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