39) Correct option is :(d) 4 ( because first ionization energy is lower.)
40) Correct option is : (a) Energy is put in ( to remove electron from Na, known as ionisation energy)
42) Correct option is : (b) Energy is released (because energy is released due to electron gain enthalpy by accepting electron.)
43) Correct option is : (b) Energy is released (because energy is released in lattice energy )
39) A ficticious atom, Up, has the following ionization energies: 234 kJ/mol, 324 kJ/mol, 524 kJ/mol,...
Consider the following information. • The lattice energy of NaCl is AHlattice = –788 kJ/mol. • The enthalpy of sublimation of Na is AHsub = 107.5 kJ/mol. • The first ionization energy of Na is IE1 = 496 kJ/mol. • The electron affinity of Cl is AHEA = -349 kJ/mol. • The bond energy of Cl, is BE = 243 kJ/mol. Determine the enthalpy of formation, AHf, for NaCl(s). AH= kJ/mol
Consider the following information. The lattice energy of NaCl is ΔH lattice=−788 kJ/mol The enthalpy of sublimation of Na is ΔHsub=107.5 kJ/mol The first ionization energy of Na is IE1=496 kJ/mol. The electron affinity of Cl is ΔHEA=−349 kJ/mol. The bond energy of Cl2 is BE=243 kJ/mol. Determine the enthalpy of formation, ΔHf, for NaCl(s). ΔHf= kJ/mol
A neutral atom has the following ionization energies given in KJ/mol: 1st Ionization energy:578 2nd ionization energy:1000 3rd ionization energy: 7745 4th ionization energy: 9,577 the element can be: ? a) phosphorus b) sodium c) beryllium d) aluminum e) carbon A typed answer is preferd. Please explain why.
Use bond energies, values of electron affinities, and the ionization energy of hydrogen (1312 kJ/mol) to estimate AH for the following reaction Bond Energies Electron Affinities H-F (565 kJ/mol) F() (-328 kJ/mol) H-CI (427 kJ/mol) C1(9) (-349 kJ/mol) -(295 kJ/mol) 1(9) (-295 kJ/mol) 0_H(467 kJ mol) OH(g) (-180. kJ/mol) H2O(g) + H+ (g) + OH (9) AHL b HCI(g) + H+ (g) + CI" (9) AH = kJ
Part A. Given the bond dissociation energies (in kJ/mol) for the following diatomic molecules Cl2 (243), F2 (158), H2 (436), O2 (498), N2 (945) choose the one(s) that could be broken by using blue light (λ=465 nm). Part B. Given the bond energies (in kJ/mol) of the following bonds: F–F (155), F–Cl (193), and Cl–Cl (243), estimate the molar enthalpy of formation of ClF(g), that is find ∆H for the following reaction ½Cl2(g) + ½F2(g) → ClF(g)
Given the bond energies (in kJ/mol) of the following bonds: F–F (155), F–Cl (193), and Cl–Cl (243), estimate the molar enthalpy of formation of ClF(g), that is find ∆H for the following reaction ½Cl2(g) + ½F2(g) → ClF(g) A. 209 kJ/mol B. -50. kJ/mol C. –8 kJ/mol D. –209 kJ/mol E. 8 kJ/mol
8. Given the following bond dissociation energies, what is the AF" for the formation of hydrogen chloride? H2(g) + Cl2(g) → 2 HCI(g) Bond Energy (kJ/mol) Bond 436 243 432 H-H Cl-CI H-Cl A) 185 kJ/mol. B) -92.5 k.J/mol. C) 92.5 kJ/mol. D) -185 kJ/mol.? E) 277.5 kJ/mol.
Please explain 25) What period 3 element has the following ionization energies (all in kJ/mol)? 25) IE1 - 738 IE2 14450 IE3 16400 IE4 17600 IE5-18820 IE6 19900 A) P B) Si C) CI D) Mg E) Na
Name: Quiz 9 CHE 1030 1. Using the following bond energies Bond Energy (kJ/mol) 839 413 495 799 467 Bond C-H O-0 C-O O-H estimate the heat of combustion for 1 mol of acetylene: C2H2(g)+ O2(g) → 2CO2(g)+H2O(g) 2. Using the following data reactions: H2(g) + Cl2(g) → 2HCl(g) H2(g) → 2H(g) Cl2(g) 2CIg) AP (kJ) -184 432 239 calculate the energy of an H-Cl bond.
1. Which one of the following is most likely to be an ionic compound? A) CaCl2 B) CO2 C) CS2 D) SO2 E) OF2 2. Which one of the following ionic solids would have the largest lattice energy? A) NaCl B) NaF C) CaBr2 D) CsI E) CaCl2 3. Calculate the energy change for the reaction K(g) + I(g) → K+(g) + I – (g) given the following ionization energy (IE) and electron affinity (EA) values. IE K: 419 kJ/mol...