k(q)^2 / r = mv^2 please solve for v where k = 8.99x10^9 C, q =...
k(q)^2 / r = mv^2 please solve for v where k = 8.99x10^9 C, q = 10x10^-6 C, r = 0.055m, m = .001g. This problem is solving for electric potential energy and electric potential the right answer is V = 4.04x10^3 m/s. But I keep getting the wrong answer please do a step by step to show me thank you.
Homework Answers
Solution)
Kq^2/r= mv^2
(8.99*10^9)*(10*10^-6)^2/0.055 =0.001*10^-3 *v^2
16.34= 10^-6 * V^2
So, V= 4042.27 = 4.04*10^3 m/s
========
Good luck:)
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and I put this number and the given numbers to find 'r', but I
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This is what I did.
r = (m*v) / (qB)
To find v, v= sqrt( 2*q*V/m) = 37013.9
and I put this number and the given numbers to find 'r', but I
got it wrong. What did I do wrong?
I. Suppose that an ion source in a mass spectrometer produces doubly ionized gold ions (Au2+), each with a mass of 3.27 × 10-25 kg The ions are accelerated from rest through a potential difference of 1.40 kV. Then, a...
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