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A mixture of 82.5 g of aluminum and 117.6 g of oxygen is allowed to react....

A mixture of 82.5 g of aluminum and 117.6 g of oxygen is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete

Balanced equation:
4 Al + 3 O2 ===> 2 Al2O3

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Answer #1

- Ans - The given reaction is - 4 AL +30 2 Algo . From the balanced reaction, we have, 4 moes of Al reacts with 3 moles of O2So, 95,94 g of Oz Jearts with 107.92 g of Al. 2) 117.6g of O2 will react with 107.92 x 117,69 of Al 95.94 - 12691.392 g of AlThus only 72,34 g of oxygen to complite the reaction as g of aluminium is grew . is woed only 82.5 But 117.6 g of oxygen is p

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