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Answer:-
This question is solved by using the simple concept of stoichiometry whinch involves the relationship between masses of reactants and products.
The answer is given in the image,
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0.320 mol of octane is allowed to react with 0.840 mol of oxygen.
which is the...
balanced chemical equation: 2C8H18(g)+25O2->16CO2(g)+18H2O(g) 0.320 mol of octane is allowed to react with 0.880 mol of...
balanced chemical equation: 2C8H18(g)+25O2->16CO2(g)+18H2O(g) 0.320 mol of octane is allowed to react with 0.880 mol of oxygen. After the reaction how much Octane is left?
Balanced chemical equation: 2C8H18(g)+25O2(g)->16CO2(g)+18H2O(g) 0.320 mol of octane is allowed to react with 0.880 mol of...
Balanced chemical equation: 2C8H18(g)+25O2(g)->16CO2(g)+18H2O(g) 0.320 mol of octane is allowed to react with 0.880 mol of oxygen. How many moles of water are produced in this reaction?
Octane (C3H18) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). When the...
Octane (C3H18) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). When the equation below is balanced, the coefficient of octane is: C8H18 + O2-CO2 + H20
Part A Determine the balanced chemical equation for this reaction. C8H18(g)+O2(g)?CO2(g)+H2O(g) Enter the coefficients for each...
Part A Determine the balanced chemical equation for this reaction. C8H18(g)+O2(g)?CO2(g)+H2O(g) Enter the coefficients for each compound in order, separated by commas. For example, 1,2,3,4 would indicate one mole of C8H18, two moles of O2, three moles of CO2, and four moles of H2O. 2,25,16,18 SubmitHintsMy AnswersGive UpReview Part Correct It is important to balance a chemical equation before using it for calculations. Checking that equations are balanced will help you avoid many errors in chemistry problems. Balanced chemical equation...
A mixture of 82.5 g of aluminum and 117.6 g of oxygen is allowed to react....
A mixture of 82.5 g of aluminum and 117.6 g of oxygen is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete Balanced equation: 4 Al + 3 O2 ===> 2 Al2O3
cal 22) Given that 4 NH3 5 O2-4 NO+6 HyO, if 3.00 mol NH3 were made to react with excess of 22) Oxygen gas, the amo...
cal 22) Given that 4 NH3 5 O2-4 NO+6 HyO, if 3.00 mol NH3 were made to react with excess of 22) Oxygen gas, the amount of H2O formed would be A) 4.50 mol. B) 2.00 mol. C) 6.00 mol. D) 3.00 mol. E) none of the above 23) Which of the following statements is FALSE? A) The actual yield is the amount of product actually produced by a chemical reaction. B) The percent yield- 23) Actual Yield Theoretical Yield...
22) Given that 4 NH3 +50,-- 4 NO:6 HO.if 3.00 mol NHy were made to react with excess of oxygen gas, the amount of H...
22) Given that 4 NH3 +50,-- 4 NO:6 HO.if 3.00 mol NHy were made to react with excess of oxygen gas, the amount of H2O formed would be: A) 4.50 mol B) 2.00 mol. C) 6.00 mol. D) 3.00 mol. E) none of the above 23) Which of the following statements is FALSE? A) The actual yield is the amount of product actually produced by a chemical reaction. B) The percent yield - Actual Yield Theoretical Yield"100 C) The limiting...
Liquid octane CH3CH26CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O....
Liquid octane CH3CH26CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 8.00 g of octane is mixed with 21. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.
Octane (C8H18) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O).
Octane (C8H18) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). When the equation in balanced, the coefficient of octane is: C8H18+ O2 --> CO2 + H2O a.8 b. 16 c.25 d. 2
Liquid octane CH3CH26CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and...
Liquid octane CH3CH26CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 1.14 g of octane is mixed with 8.0 g of oxygen. Calculate the minimum mass of octane that could be left over by the chemical reaction. Be sure your answer has the correct number of significant digits.
Octane (C3H18) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). When the equation below is balanced, the coefficient of octane is: C8H18 + O2-CO2 + H20
cal 22) Given that 4 NH3 5 O2-4 NO+6 HyO, if 3.00 mol NH3 were made to react with excess of 22) Oxygen gas, the amount of H2O formed would be A) 4.50 mol. B) 2.00 mol. C) 6.00 mol. D) 3.00 mol. E) none of the above 23) Which of the following statements is FALSE? A) The actual yield is the amount of product actually produced by a chemical reaction. B) The percent yield- 23) Actual Yield Theoretical Yield...
22) Given that 4 NH3 +50,-- 4 NO:6 HO.if 3.00 mol NHy were made to react with excess of oxygen gas, the amount of H2O formed would be: A) 4.50 mol B) 2.00 mol. C) 6.00 mol. D) 3.00 mol. E) none of the above 23) Which of the following statements is FALSE? A) The actual yield is the amount of product actually produced by a chemical reaction. B) The percent yield - Actual Yield Theoretical Yield"100 C) The limiting...
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