Question

cal 22) Given that 4 NH3 5 O2-4 NO+6 HyO, if 3.00 mol NH3 were made to react with excess of 22) Oxygen gas, the amount of H2O formed would be A) 4.50 mol. B) 2.00 mol. C) 6.00 mol. D) 3.00 mol. E) none of the above 23) Which of the following statements is FALSE? A) The actual yield is the amount of product actually produced by a chemical reaction. B) The percent yield- 23) Actual Yield Theoretical Yield x 100% . C) The limiting reactant is completely consumed in a chemical reaction D) The theoretical yield is the amount of product that can be made based on the amount of limiting reagent. E) All of the above are true statements 24) Consider the following generic chemical equation: 2W +3X3Y+Z When 5 units of W and 6 units of X are allowed to react, the limiting reactant would be A) X 24) B) W C) Y D) Z E) There is no limiting reactant in this situation. 25) A balanced chemical equation used to prepare ammonium carbonate, (NH4)2CO3, is: 25) 2 NH3 CO2 H20-(NH4)2CO3 Which choice of reactant quantities shown below would result in the greatest amount of ammonium carbonate being formed? A) React 2 moles NH3, 8 moles CO2, and 8 moles H2O B) React 2 moles NH3, 1 mole CO2, and 1 mole H2o C) React 4 moles NH3, 1 mole CO2, and 2 moles H2O D) React 4 moles NH3 , 2 moles CO2, and 2 moles HyO E) none of the above 26) What is the theoretical yield of a reaction if 25.0 grams of product were actually produced from a 26) reaction that has a 88% yield ? A) 3.52 B) 28.4 C) 352 D) 22.0 E) none of the above ORT

Answer 1

Soluliön !- 4 NH3 +502 Amole Eess 4no + 6H20 6 mol 2 mol 3 mole Ўси =) & mole any react to produce = 6 mole 420 - 3 mole ons will react to produce = 673 mol 120 -4.5 mole H2O - Answer: A) 4.50 mole 23) E) all of the above are from statement] 2W+34 3Y+ZI a mol 3 mol - 2 mo| w gеthі» 3 моl x Given! 5 mol 6 mol - 5 mol w will react with = 3 XS molt = 7-5 molx but given molalx=6 : Wis exars whils xin limity reactant - Answer: A) X

251 2NH3 + CO2 + H20 Corny) cez amole Imol Imole imob Angulo: D Realt & mobnas, z mole CO2, z molto 202 actual gield= 25g Percent gield = 88y. . ho cenos, percent yidd - actual gield 4100 Theoretical yield - Xlob Theoretical field = actual yield Percent yield = 25 x los = 28.409 g . Answer: 8) 28.4