Question

1. For the balanced chemical reaction: 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(ℓ), how many moles of H2O are produced when 0.669 mol of NH3 react?

2.For the balanced chemical reaction: 4 KO2(s) + 2 CO2(g) → 2 K2CO3(s) + 3 O2(g)
determine the number of moles of each of the products that are formed when 6.88 mol of KO2 react.

Please explain, thanks!

Answer 1

1) vн ала 4NH₃ + 50₂ 4NO + 6H₂O How many moles of H2O is produced when 0.669 moles of NH3 reacts? solution 4 moles of NH₃ produus 6moles of Ho I mole of NH3 produus & moles of H2o. 0.669 moles of NH3 produus x 0.669 moles of H2O = 1.0035 moles of H2O given reaction 4ko + 2 co2 ak ₂CO3 + 302 4 moles of KO2 reacts to give Imole of KO reacts to give 6.88 mole of KO₂ reacts to give a moles of Kz cog a moles of K2CO3 2x6.88 moles of K₂ CO 3 = 3.44 moles of K₂CO₃ 4 moles of ko reacts to release 3 moles of O₂ gas I mole of KOL reacts to release 3 moles of a gas 6.88 moles of KO2 react to release 3 3 x 6.88 moles of a gas = 5.16 moles of or gas Ars: 6.88 moles of Kol gives 3.44 moles of K2O3 and 5.16 moles of or go