Question

According to the balanced reaction below, calculate the moles of NH3 that form when 4.2 mol of N2H4 completely reacts 3 N2H4(
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Answer #1

1)

From balanced equation,

Mol of NH3 formed = (4/3)*mol of N2H4 reacted

= (4/3)*4.2 mol

= 5.6 mol

Answer: 5.6 mol

2)

From balanced equation,

Mol of NO2 formed = (4/2)*mol of N2O5 reacted

= (4/2)*(5.20*10^-3) mol

= 0.0104 mol

Answer: 0.0104 mol

3)

From balanced equation,

Mol of H2SO4 required = (3/2)*mol of Al reacted

= (3/2)*7.20 mol

= 10.8 mol

Answer: 10.8 mol

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