1)
From balanced equation,
Mol of NH3 formed = (4/3)*mol of N2H4 reacted
= (4/3)*4.2 mol
= 5.6 mol
Answer: 5.6 mol
2)
From balanced equation,
Mol of NO2 formed = (4/2)*mol of N2O5 reacted
= (4/2)*(5.20*10^-3) mol
= 0.0104 mol
Answer: 0.0104 mol
3)
From balanced equation,
Mol of H2SO4 required = (3/2)*mol of Al reacted
= (3/2)*7.20 mol
= 10.8 mol
Answer: 10.8 mol
Only 1 question at a time please
According to the balanced reaction below, calculate the moles of NH3 that form when 4.2 mol of N2H4 completely reac...
please answer question in the boxes for all problems According to the balanced reaction below, calculate the moles of NH3 that form when 4.2 mol of N2He completely reacts 3 N2H4(1) ► 4 NH3(g) + N2(g) STARTING AMOUNT ADD FACTOR ANSWER RESET 16.8 5.6 32.06 4 4.2 28.02 | 3.2 Tap here or pull up for additional resources How many moles of Care formed upon complete reaction of 2 mol of B according to the generic chemical reaction: A +...
Question 1 of 23 According to the balanced reaction below, calculate the moles of NH3 that form when 4.2 mol of N2H4 completely reacts 3 N2H.(I) — 4 NH3(g) + N2(g) How many moles of H2SO, are required to completely react with 7.20 mol of Al according to the balanced chemical reaction: 2 Al(s) + 3 H2SO,(aq) — AIZ(S0a)3(aq) + 3 H2(g)
according to the balanced reaction below, calculate the moles of NO2 that form when 5.20×10-3 mol of N2O5 completely reacts 2N2O5g>4No2g+O2g
You may want to reference (Pages 141-145) Section 4.2 while completing this problem. Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation 3 N2H4(l) → 4 NH3(g)+N2(g) Part A 2.5 moles N2H4Part B 3.55 mol N2H4 Part C 61.3 g N2H4 Part D 4.58 kg N2H4
For the reaction shown, calculate how many moles of NO2 form when each amount of reactant completely reacts. 2N2O5(g)→4NO2(g)+O2(g) A. 1.6 mol N2O5 B. 6.0 mol N2O5 C. 5.27×103 mol N2O5 D. 1.010×10−3 mol N2O5
For the reaction shown, calculate how many moles of NO2 form when each amount of reactant completely reacts. 2N2O5(g)→4NO2(g)+O2(g) Part A 1.4 mol N2O5 Part B 5.6 mol N2O5 Part C 12.5 g N2O5 Part D 1.75 kg N2O5
According to the UNBALANCED reaction below, calculate the number of moles of NH3 that will form when 12.7 moles of N2H4completely react: N2H4 --> NH3 + N2
calculate how many moles of NO2 form when each quantity of reactant completely reacts. 2N2O5(g)--->4NO2(g)+O2(g) a. 2.5 mol N2O5 b. 6.8 mol N2O5 c. 15.2 g N2O5 d. 2.87 kg N2O5
According to the balanced equation below, when 4 mol of butane (C4H10) undergo combustion, how many moles of CO2 are produced? 2 C4H10() + 13 O2(g) → 8 CO2(g) + 10 H2O(9) O2 04 08 16 32
Question 3 of 10 Submit Balance the following chemical equation (if necessary): Na3PO4(aq) + NiCiz (aq) → Ni3(PO4)2 (s) + NaCl(aq) Reset 30,2 Reset 60 @ 1 2 3 4 5 6 800 (s) 0 (g) (aq) Nis(POA)2 Nacı Na PO. Niclz • x H20 Question 4 of 10 Submit Balance the following chemical equation (if necessary): C3H6(g) + O2(g) + CO2(g) + H2O(g) Reset 30,2 Reset 60 @ 123460089 (aq) (s) CO2 (1) H20 (g) Oz CsHo • «...