Question

Yo c PH1012 /15 Q6 (15 marks) Figure 6(a) shows a circuit where Vi, V2, Va, V4, Vs, V = 1 V, 2 V,3 V,4 V,5 V,6 V respectively Calculate the current passing through R2. respectively. 10,2 Ω,3 Ω.4 Ω,5 Ω, 6 Ω and R, , R , R3, R4, R, R, R1 V1 V3 R2 R6 R3 V2 V4 V6 V5 R5 R4 Figure 6(a) 1+I 13.

Any idea how do I get all the respective currents??

Answer 1

Vi = 1 R = 16 V3 = 34 &R3=30 6.12- R2 =21 12 +12=24 6V = VET ve 15:5V Rg=52 42 = 24 14- = 44 Apply mesh analysis an Loop 1: - Vo + I, R& -V, + ITR + R2 (1,-12) + V2 + RST, - V5 = 0 (R6+ R1 + R2 +R5) I, - (R2) I2 = (V6+v; +45 -42) (6+1+2 +511, - 2 12 = 6+1+5-2 143, -212 = 10 On Loop 2 : - V2 + R2 (12-31) - V3 + R3I2 + 14 + R4I2 = 0 - R2 I, + (R2+R3 +R4)12 = (v2 + V3 - VA) - 2I, + 2+3+4) I2 = (2+ 3-4) -21, + 912 = 1 - from equat multiply by 7 anich add to Egy © . 1971-232 = 10 - 0 -14 12 +6312 = 7 -O 12 = 17%, A I, – 46/41A - current through. R2 = TR2 = 1,-22 = 46-17 = 29 A Because RscRo and Ry are msenies .. FRS – IR6 = FR = I q = 7,6. A .: Beca R2 md Rq are an Series Tra = IRe = 12 = 17 A

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