The first eight ionization energies of a third row element are
999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol.
Identify the element.
Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH.
Si
The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004,...
The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol. Identify the element. Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH. Si
The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol. Identify the element. Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH. Si
The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol. Identify the element. Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH. Si
The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol. Identify the element. Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH. Si
Part A What is the third-row element having the successive ionization energies in kJ/mol: 738, 1451, 7733, 10,540, 13,630, 17,995, 21,703 Express your answer as a chemical symbol Submit Previous Answers Request Answer X Incorrect: Try Again; 3 attempts remaining Provide Feedback Next>
please explain why 3. The first six ionization energies (kJ/mol) of a certain SECOND-ROW element are as follows: Ij = 1,086 12 = 2350 13 = 4620 14 = 6220 Is = 38,000 16 = 47,261 The most likely identity of this element is a) B b) 0 c) N d) Be e) C