Homework Answers
There is an abrupt increase in 4th ionization energy value.
I1,I2,I3, I4 values
have only gradual increase. So the abrupt increase in the removal
of 5th electron
indicate ,its valancy is 4. Hence the element is carbon whose
valancy is 4
option E:: Carbon
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please explain why 3. The first six ionization energies (kJ/mol) of a certain SECOND-ROW element are...
9. A certain 4th row element has the following ionization energies: 12 = 1310 kJ/mol I3...
9. A certain 4th row element has the following ionization energies: 12 = 1310 kJ/mol I3 = 2652 kJ/mol 14 = 4175 kJ/mol Is = 9581 kJ/mol 16 = 11533 kJ/mol Now tell me, most peerless predictor of periodic properties, what is the identity of the element? Please provide an explanation as well.
11. The successive ionization energies of a certain element in period 5 are 577.9 kl/mol, 1x...
11. The successive ionization energies of a certain element in period 5 are 577.9 kl/mol, 1x = 1820 kl/mol, 13- 2750 kJ/mol, 14 = 11,600 kl/mol, and is = 14,800 kl/mol. Determine the identity of this unknown element. Justify your answer utilizing periodic trends.
a new element X is discovered that has the following successive ionization energies (kj/mol) IE1=1004 ,...
a new element X is discovered that has the following successive ionization energies (kj/mol) IE1=1004 , IE2=1251 IE3=5988 , IE4=6220 , IE5=6803 , IE6=7178 a. what group (column) do you expect this element will belong? explain b. if this element X combined with fluorine , what is the likely molecular formula?( for example XF2, X2F3, etc)
The first three ionization energies for element Z are 320 kJ/mol, 640 kJ/mol, 10,200 kJ, mol....
The first three ionization energies for element Z are 320 kJ/mol, 640 kJ/mol, 10,200 kJ, mol. What is the likely charge of Z Z+ Z2+ Z3+ Z4+
15. Below is a list of successive ionization energies (in kJ/mol) for a period 3 element,...
15. Below is a list of successive ionization energies (in kJ/mol) for a period 3 element, X. What is the most likely formula for a stable ion of X? 151 = 1000 IE2 = 2250 IE3 = 3360 IE4= 4560 E5= 7010 TE6= 8500 IE2 = 27.100 d. X a. X2 b. X30 c. X²
The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004,...
The first eight ionization energies of a third row element are
999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol.
Identify the element.
Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH.
Si
The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004,...
The first eight ionization energies of a third row element are
999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol.
Identify the element.
Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH.
Si
The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004,...
The first eight ionization energies of a third row element are
999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol.
Identify the element.
Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH.
Si
The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004,...
The first eight ionization energies of a third row element are
999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol.
Identify the element.
Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH.
Si
The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004,...
The first eight ionization energies of a third row element are
999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol.
Identify the element.
Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH.
Si
9. A certain 4th row element has the following ionization energies: 12 = 1310 kJ/mol I3 = 2652 kJ/mol 14 = 4175 kJ/mol Is = 9581 kJ/mol 16 = 11533 kJ/mol Now tell me, most peerless predictor of periodic properties, what is the identity of the element? Please provide an explanation as well.
11. The successive ionization energies of a certain element in period 5 are 577.9 kl/mol, 1x = 1820 kl/mol, 13- 2750 kJ/mol, 14 = 11,600 kl/mol, and is = 14,800 kl/mol. Determine the identity of this unknown element. Justify your answer utilizing periodic trends.
15. Below is a list of successive ionization energies (in kJ/mol) for a period 3 element, X. What is the most likely formula for a stable ion of X? 151 = 1000 IE2 = 2250 IE3 = 3360 IE4= 4560 E5= 7010 TE6= 8500 IE2 = 27.100 d. X a. X2 b. X30 c. X²
The first eight ionization energies of a third row element are
999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol.
Identify the element.
Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH.
Si
The first eight ionization energies of a third row element are
999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol.
Identify the element.
Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH.
Si
The first eight ionization energies of a third row element are
999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol.
Identify the element.
Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH.
Si
The first eight ionization energies of a third row element are
999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol.
Identify the element.
Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH.
Si
The first eight ionization energies of a third row element are
999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol.
Identify the element.
Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH.
Si
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