a new element X is discovered that has the following successive ionization energies (kj/mol) IE1=1004 ,...

Question

Question

a new element X is discovered that has the following successive ionization energies (kj/mol)

IE1=1004 , IE2=1251 IE3=5988 , IE4=6220 , IE5=6803 , IE6=7178

a. what group (column) do you expect this element will belong? explain

b. if this element X combined with fluorine , what is the likely molecular formula?( for example XF2, X2F3, etc)

Answer 1

Answer #1

IE1= 1004

IE2= 1251

IE3= 5988

There is sudden jump from IE2 to IE3.

These observations give information that that element has 2 valence electrons in its outermost shell. It belongs group 2. i.e alakakine earth metals

M⁺² is the stable and its valence is 2.

Molecular formula of its fluoride is MF₂

Answer 2

Similar Homework Help Questions

Consider the following set of successive ionization energies: IE1 = 578kJ/mol IE2 = 1,820kJ/mol IE3 =...

Consider the following set of successive ionization energies: IE1 = 578kJ/mol IE2 = 1,820kJ/mol IE3 = 2,750kJ/mol IE4 = 11,600kJ/mol IE5 = 13,300kJ/mol To which second period element do these ionization values belong?
Question 6 0.15 pts Consider the following set of successive ionization energies: IE1 = 578kJ/mol IE2...

Question 6 0.15 pts Consider the following set of successive ionization energies: IE1 = 578kJ/mol IE2 = 1,820kJ/mol IE3 = 2,750kJ/mol IE4 = 3,600kJ/mol IE5 = 13,300kJ/mol To which second period element do these ionization values belong? Enter your answer as a chemical symbol (ex: He).
Identify the group number of the element that has the following successive ionization energies (in kJ/mol). IE1 = 1...

Identify the group number of the element that has the following successive ionization energies (in kJ/mol). IE1 = 1,060 IE5 = 6,270 1E4 = 4,950 IE2 = 1,890 IE6 = 21,200 E3 = 2,905 IE7 = 25,400 Group 5A O Group 7A Group 4A Group 3A O Group 6A

4. Consider an element of Period 2 which has the following successive ionization energies, in kJ/mol....

4. Consider an element of Period 2 which has the following successive ionization energies, in kJ/mol. What is the charge of the common ion? IE1, 1314 IE2, 3389 IE3, 5298 IE4, 7471 IEs, 10992 IE6, 13329 IE7, 71345 IE8, 84087 (1) -1 (2) –2 (3) –3 (4) +6 (5) +7
Please explain 25) What period 3 element has the following ionization energies (all in kJ/mol)? 25)...

Please explain 25) What period 3 element has the following ionization energies (all in kJ/mol)? 25) IE1 - 738 IE2 14450 IE3 16400 IE4 17600 IE5-18820 IE6 19900 A) P B) Si C) CI D) Mg E) Na
Consider this set of ionization energies. IE1 = 578 kJ/mol, IE2 = 1820 kJ/mol, IE3 =...

Consider this set of ionization energies. IE1 = 578 kJ/mol, IE2 = 1820 kJ/mol, IE3 = 2750 kJ/mol, IE4 = 11,600 kJ/mol. To which third-period element do these ionization energies belong?

Identify the element of Period 2 (name) which has the following successive ionization energies, in kJ/mol....

Identify the element of Period 2 (name) which has the following successive ionization energies, in kJ/mol. IE1 = 1314 IE2 = 3388 1E3 = 5301 JE4 = 7469 IE5 = 10989 IE6 = 13327 1E7 = 71330 IE8 = 84078 Answer:
10.) Below is a list of successive ionization energies (in kJ/mol) for a period 3 element....

10.) Below is a list of successive ionization energies (in kJ/mol) for a period 3 element. Identify the element and explain how you came to that conclusion. IE2 = 2250 IE3 - 3360 TE 4 = 4560 IE5 = 7010 IE6 - 8500 IE 7 = 27,100
Question 2 1 pts Identify the group number of the element that has the following successive...

Question 2 1 pts Identify the group number of the element that has the following successive ionization energies (in kJ/mol). IE1 = 590 IE5 = 8,153 IE2 = 1,145 IE6 = 10,490 IE3 = 4,912 IE4 = 6,490 E7 = 12,270 Group 5A Group 2A O Group 4A O Group 3A Group 6A

15. Below is a list of successive ionization energies (in kJ/mol) for a period 3 element,...

15. Below is a list of successive ionization energies (in kJ/mol) for a period 3 element, X. What is the most likely formula for a stable ion of X? 151 = 1000 IE2 = 2250 IE3 = 3360 IE4= 4560 E5= 7010 TE6= 8500 IE2 = 27.100 d. X a. X2 b. X30 c. X²