10.) Below is a list of successive ionization energies (in kJ/mol) for a period 3 element....
15. Below is a list of successive ionization energies (in kJ/mol) for a period 3 element, X. What is the most likely formula for a stable ion of X? 151 = 1000 IE2 = 2250 IE3 = 3360 IE4= 4560 E5= 7010 TE6= 8500 IE2 = 27.100 d. X a. X2 b. X30 c. X²
what is the answer to question number 4? 1) Describe how a neon light works. (Discussion must include information about the Neon atoms, specific wavelength and transitions) 2) What is the photoelectric effect? 3) Sketch one of the 3p orbitals below. How are they different from the 2p orbitals? 4) Below is a list of successive ionization energies (in kJ/mol) for a period 3 element. Identify the element and explain how you came to that conclusion. IE2 2250 IE3 -3360...
Identify the element of Period 2 (name) which has the following successive ionization energies, in kJ/mol. IE1 = 1314 IE2 = 3388 1E3 = 5301 JE4 = 7469 IE5 = 10989 IE6 = 13327 1E7 = 71330 IE8 = 84078 Answer:
a new element X is discovered that has the following successive ionization energies (kj/mol) IE1=1004 , IE2=1251 IE3=5988 , IE4=6220 , IE5=6803 , IE6=7178 a. what group (column) do you expect this element will belong? explain b. if this element X combined with fluorine , what is the likely molecular formula?( for example XF2, X2F3, etc)
Please explain 25) What period 3 element has the following ionization energies (all in kJ/mol)? 25) IE1 - 738 IE2 14450 IE3 16400 IE4 17600 IE5-18820 IE6 19900 A) P B) Si C) CI D) Mg E) Na
4. Consider an element of Period 2 which has the following successive ionization energies, in kJ/mol. What is the charge of the common ion? IE1, 1314 IE2, 3389 IE3, 5298 IE4, 7471 IEs, 10992 IE6, 13329 IE7, 71345 IE8, 84087 (1) -1 (2) –2 (3) –3 (4) +6 (5) +7
Identify the group number of the element that has the following successive ionization energies (in kJ/mol). IE1 = 1,060 IE5 = 6,270 1E4 = 4,950 IE2 = 1,890 IE6 = 21,200 E3 = 2,905 IE7 = 25,400 Group 5A O Group 7A Group 4A Group 3A O Group 6A
Consider the following set of successive ionization energies: IE1 = 578kJ/mol IE2 = 1,820kJ/mol IE3 = 2,750kJ/mol IE4 = 11,600kJ/mol IE5 = 13,300kJ/mol To which second period element do these ionization values belong?
Question 2 1 pts Identify the group number of the element that has the following successive ionization energies (in kJ/mol). IE1 = 590 IE5 = 8,153 IE2 = 1,145 IE6 = 10,490 IE3 = 4,912 IE4 = 6,490 E7 = 12,270 Group 5A Group 2A O Group 4A O Group 3A Group 6A
Which element in row two would have the following ionization energies? Ionization energies are given in kJ/mol. IE3 = 4.58, IE4 = 7.48, IE5 = 9.44, IE6 = 53.27