There is huge difference in energy between IE5 and IE6
So, atom must have acquired noble gas configuration after removing 5 electrons.
So, there are 5 valence electrons.
So, it must belong to Group 5A
Answer: Group 5A
Identify the group number of the element that has the following successive ionization energies (in kJ/mol). IE1 = 1...
Question 2 1 pts Identify the group number of the element that has the following successive ionization energies (in kJ/mol). IE1 = 590 IE5 = 8,153 IE2 = 1,145 IE6 = 10,490 IE3 = 4,912 IE4 = 6,490 E7 = 12,270 Group 5A Group 2A O Group 4A O Group 3A Group 6A
Question 2 1 pts Identify the group number of the element that has the following successive ionization energies (in kJ/mol). IE2 - 577 1 E2 - 1,816 IE3 - 2,881 1E4 - 11,600 IES - 14,800 1E6 - 18,400 IE2 = 23,300 Group 3A Group 5A Group 2A Group 6A Group 7A
a new element X is discovered that has the following successive ionization energies (kj/mol) IE1=1004 , IE2=1251 IE3=5988 , IE4=6220 , IE5=6803 , IE6=7178 a. what group (column) do you expect this element will belong? explain b. if this element X combined with fluorine , what is the likely molecular formula?( for example XF2, X2F3, etc)
Identify the element of Period 2 (name) which has the following successive ionization energies, in kJ/mol. IE1 = 1314 IE2 = 3388 1E3 = 5301 JE4 = 7469 IE5 = 10989 IE6 = 13327 1E7 = 71330 IE8 = 84078 Answer:
Question 5 1 pts Identify the group number of the element that has the following successive ionization energies (in kJ/mol). IE1-577 IEs 14,800 IE6 18,400 IE 23,300 E2-1,816 IE3 2,881 IE4 -11,600 O Group 2A O Group 7A O Group 3A O Group 5A Previous Next
4. Consider an element of Period 2 which has the following successive ionization energies, in kJ/mol. What is the charge of the common ion? IE1, 1314 IE2, 3389 IE3, 5298 IE4, 7471 IEs, 10992 IE6, 13329 IE7, 71345 IE8, 84087 (1) -1 (2) –2 (3) –3 (4) +6 (5) +7
Consider the following set of successive ionization energies: IE1 = 578kJ/mol IE2 = 1,820kJ/mol IE3 = 2,750kJ/mol IE4 = 11,600kJ/mol IE5 = 13,300kJ/mol To which second period element do these ionization values belong?
10.) Below is a list of successive ionization energies (in kJ/mol) for a period 3 element. Identify the element and explain how you came to that conclusion. IE2 = 2250 IE3 - 3360 TE 4 = 4560 IE5 = 7010 IE6 - 8500 IE 7 = 27,100
Question 6 0.15 pts Consider the following set of successive ionization energies: IE1 = 578kJ/mol IE2 = 1,820kJ/mol IE3 = 2,750kJ/mol IE4 = 3,600kJ/mol IE5 = 13,300kJ/mol To which second period element do these ionization values belong? Enter your answer as a chemical symbol (ex: He).
Please explain 25) What period 3 element has the following ionization energies (all in kJ/mol)? 25) IE1 - 738 IE2 14450 IE3 16400 IE4 17600 IE5-18820 IE6 19900 A) P B) Si C) CI D) Mg E) Na