Homework Answers
a) here as k score=(X-mean)/std deviation
therefore P(55<X<75)=P((55-65)/5<Z<(75-65)/5)=P(-2<Z<2) =95%
b)
P(60<X<70)=P((60-65)/5<Z<(70-65)/5)=P(-1<Z<1) =68.0%
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