Question

10.1 A. Calculate the mean and standard deviation of the following securities’ returns: Year Computroids Inc....

10.1 A. Calculate the mean and standard deviation of the following securities’ returns: Year Computroids Inc. Blazers Inc. 1 10% 5% 2 5% 6% 3 –3% 7% 4 12% 8% 5 10% 9%

B. Assuming these observations are drawn from a normally distributed probability space, we know that about 68% of values drawn from a normal distribution are within one standard deviation away from the mean or expected return; about 95% of the values are within two standard deviations; and about 99.7% lie within three standard deviations. Using your calculations from part A, calculate the 68%, 95%, and 99% confidence intervals for the two stocks. To calculate the 68%, you would calculate the top of the confidence interval range by adding one standard deviation to the expected return, and calculate the bottom of the confidence interval by subtracting one standard deviation from the expected return. For 95%, use two standard deviations, and for 99%, use three. Your answer should show three ranges from the bottom of the confidence interval to the top of the confidence interval.

C. For each security, would a return of 14% fall into the 68% confidence interval range? If not, what confidence interval range would it fall into, or would it be outside all three confidence intervals? (This is the same as asking whether a return of 14% has less than a 68% probability of occurring by chance for that security. If it’s not inside the 68% confidence interval, it’s unlikely to occur, since it will only occur by chance 32% of the time. Of course, the 99% confidence interval is much more likely to include the observed return, simply by chance. Only 1% of the time will it fall outside the 99% CI. Pretty rare.)

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Sol:

A). Mean for Computroids Inc = 10+5+(-3)+12+10= 34 / 5 = 6.8
Mean for Blazers Inc. = 5+6+7+8+9 = 35 / 5 = 7
SD for Computroids Inc = 3.80789
SD for Blazers Inc = 1.58114

B). 2.07188 ? x ? 11.52812 for Computroids at 95%
-1.04050 ? x ? 14.64050 for Computroids at 99%
5.03676 ? x ? 8.96324 for Blazers at 95%
3.74441 ? x ? 10.25559 for Blazers at 99%

C). (This is the same as asking whether a return of 14% has less than a 68% probability of occuring by chance for that security. If it’s not inside the 68% confidence interval, it’s unlikely to occur, since it will only occur by chance 32% of the time. Of course, the 99% confidence interval is muchmore likely to include the observed return, simply by chance. Only 1% of the time will it fall outside the 99% CI. Pretty rare.) I think out of all three ranges it has better luck with the 99% range for computroids. As for Blazers I don’t think 14% return would fall into any of the three categories. Computroids has the best chance at the 14% return within the 99%.

Add a comment
Know the answer?
Add Answer to:
10.1 A. Calculate the mean and standard deviation of the following securities’ returns: Year Computroids Inc....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • You are given the sample mean and the population standard deviation. Use this information to construct...

    You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 64 dates, the mean record high daily temperature in a certain city has a mean of 85.80°F. Assume the population standard deviation is 15.07°F. The 90% confidence interval is (ID). (Round to two decimal places as needed.) The...

  • You are given the sample mean and the population standard deviation. Use this information to construct...

    You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals From a random sample of 57 dates, the mean record high daily temperature in a certain city has a mean of 83.56°F. Assume the population standard deviation is 14 43°F. The 90% confidence interval is (0) (Round to two decimal places as needed.)...

  • one can calculate the 95% confidence interval for the mean with the population standard deviation knowing...

    one can calculate the 95% confidence interval for the mean with the population standard deviation knowing this gives us an upper and lower confidence limit what happens if we decide to calculate the 99% confidence interval describe how the increase in the confidence level has changed the width of the confidence interval the same for the confidence interval set at 80% including example with actual numeric value for the intervals and you're supposed to help with your explanations

  • Calciume mean = 3.14 , standard deviation = 0.46 Albumin mean = 40.4 standard deviation =...

    Calciume mean = 3.14 , standard deviation = 0.46 Albumin mean = 40.4 standard deviation = 2.46 n= 10 Q1; Construct a 99% 2-sided confidence interval for the true mean albumin levels for these patients. Q2; Construct a 99% 2-sided confidence interval for the true mean calcium levels for these patients. Q3; For healthy individuals, the normal range for calcium levels is 2.12-2.74 mmol/l and the range of normal albumin levels is 32-55g/l. Based on this information and your calculated...

  • dy/ You are given the sample mean and the population standard deviation Use this information to...

    dy/ You are given the sample mean and the population standard deviation Use this information to construct the 90% and 95% confidence intervals for the population mean Interpret the results and compare the widths of the confidence intervals From a random sample of 77 dates, the mean record high daily temperature in a certain city has a mean of 86.94°F Assume the population standard deviation is 15.31°F tiol scribe The 90% confidence interval is (1.1) (Round to two decimal places...

  • 1. Calculate the average and standard deviation for the mass of water contained in the beaker....

    1. Calculate the average and standard deviation for the mass of water contained in the beaker. What does the standard deviation tell you about the precision of the beaker? Remember that you will use your data to support your choice in your discussion. a. フ-go2 TABLE 1.10 Beaker Calibration Calculations Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 Trial 6 7.6 20 7.7907.770 7-7707.9727.755 7.6u3 7.994 7-793 7.8257.9963.02 フ·878らm4 mass water delivered volume water delivered average volume delivered...

  • 4. Given the information for the problems below, calculate the 95% confidence intervals. Report all answers to two decimal places if answer involves decimals. (a) Mean = 120, Standard Deviation = 10,...

    4. Given the information for the problems below, calculate the 95% confidence intervals. Report all answers to two decimal places if answer involves decimals. (a) Mean = 120, Standard Deviation = 10, N = 25 95% Confidence Interval From: To: (b) Mean = 24.29, Standard Deviation = 2.7, N = 140 95% Confidence Interval From: To: (c) Mean = 77.82, Standard Deviation = 5.53, N = 24 95% Confidence Interval From: To: (d) Mean = 10, Standard Deviation = 0.9,...

  • A sample of size π=95 is drawn from a population whose standard deviation is σ=27.

    A sample of size π=95 is drawn from a population whose standard deviation is σ=27. Part 1 of 2 (a) Find the margin of error for a 99% confidence interval for H. Round the answer to at least three decimal places. The margin of error for a 99% confidence interval for u is _______ . Part 2 of 2 (b) If the confidence level were 90%, would the margin of error be larger or smaller? 

  •       You take a sample of 30 items and obtain a sample mean of 15 and...

          You take a sample of 30 items and obtain a sample mean of 15 and a sample standard deviation of 5       Construct a 95% confidence interval about the mean       Construct a 99% confidence interval about the mean       If I took 100 different samples of 30 items from a given population and obtained 100 different sample means and standard deviations and formed 100 90% confidence intervals, then about how many of the confidence intervals formed from these...

  • 20 measured data points have a sample mean of 72.4 and a standard deviation of 6.89....

    20 measured data points have a sample mean of 72.4 and a standard deviation of 6.89. Estimate the range of values for which you would expect 99% of all future measurements to fall (or for a single future measurement to fall within 99% probability). Find a, where the data is expected to fall ±a about the sample mean.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT