Question

Pka of the acid is equal to pH you get at the half equivalence point (4.9)....

Pka of the acid is equal to pH you get at the half equivalence point (4.9). Find the Ka of the acid with the following equation....
pka=4.9

-log Ka= 4.9
log Ka= -4.9

Ka=?
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Answer #1

log ka = -4.9

Ka = antilog ( -4.9 )

= 1.2 * 10 -5 ( answer )

For antilog calculation, [ use next integer term ]

-4.9 = -5 ( it is used as power of 10 always ) + 0.1 (think it as log x=0.1

Then antilog value will be X * 10 ^ power

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