Question

The combustion of octane, C,Hg, proceeds according to the reaction shown. 2C,H,8 (1) + 250,(g) - 16CO2(g) + 18 H,O(1) If 4.10 x 10 mol of octane combusts, what volume of carbon dioxide is produced at 38.0 °C and 0.995 atm?

Answer 1

160gig) +8H0(L). 26 Hig (2) + 250 (g) - moles of co2 moles of C8H18 2 16 4.10x 100 2 moles of CO2 16 ncora K 6 x 410 - 3280 moles. using Pv=nRT V- ORT 3280X 0.0821x 311 0.995 = 84.1698 103 L

Mrą (s) + 4 Ha (aq) - Machlaq) +240 (L) + Chlg) (1 atm = 760 tons. moles of C = PV (98)x(100) 1805 x/145 1 0.0821* 298 - 0.0067 moles. moles of MNO2 = moles of 42 mass of Mng, = 0.0067x 87 )) 0.583 grams
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