From balanced chemical equation,
Mol of CO2 produced = (16/2)*mol of C8H18 reacted
= (16/2)*329 mol
= 2632 mol
Given:
P = 0.995 atm
n = 2632 mol
T = 18.0 oC
= (18.0+273) K
= 291 K
use:
P * V = n*R*T
0.995 atm * V = 2632 mol* 0.08206 atm.L/mol.K * 291 K
V = 6.32*10^4 L
Answer: 6.32*10^4 L
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