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The combustion of octane, C.Hgproceeds according to the reaction shown. 2CH2(1) + 250,(8) 1600, (g) + 18 H, O(1) If 394 mol o
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solution. n = 394 mol. Temp = 15°C = 15+ 27 3 = 288 K Pressure - 0.995 atm PV = nRT V=nRT R = 0.08205 Lat mkat P. mali (394x0please hit thumbs up ..if u like it

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