Question

5. 0/1 points Previous Answers SerPSE10 15.5.OP.025. My Notes A meter stick is attached to one end of a rigid rod with negligible mass of length = 0.502 m. The other end of the light rod is suspended from a pivot point, as shown in the figure below. The entire system is pulled to a small angle and released from rest. It then begins to oscillate. (a) What is the period of oscillation of the system (in s)? (Round your answer to at least three decimal places.) 2.072x Consider the moment of inertia of the meter stick alone about the pivot point. What is the distance from the pivot point to the center of mass? How does the parallel axis theorem relate the center of mass moment of inertia to the distance from the pivot to the center of mass? How is the period of a physical pendulum related to the moment of inertia and distance from the pivot to the center of mass? S (b) By what percentage does the period of the system found in part (a) differ from the period of a simple pendulum 1.002 m long? IT simple - system x 100% 0 % simple

Answer 1

metre scale will not counted in the time period of the system because it is massless.

Anwe wer) a) Tsystem= 24 0.502= Ja.8 3218 1.4218 b) Tsimple= an $2002 = 2.0088 X 100 2.008 Tsimple - Toystem = 2.008-1042) Tsimple - 0.292x100 = 29.233%