Pivot point Consider the figure Center of mass where L is the length of the e<15...
A uniform wooden meter stick has a mass of m = 799 g. A clamp can be attached to the measuring stick at any point Palong the stick so that the stuck can rotate freely about point P, which is at a distance d from the zero-end of the stick as shown. Part (a) Calculate the moment of inertia in kg-m of the meter stick if the pivot point P is at the 50-cm mark. Part (b) Calculate the moment of inertia...
A uniform rod of mass m-6 kg has length L = 60 cm . Instead of pivoting it at its end, we pivoted it at L/3 from the end as shown in the figure, we now set the rod into small angle oscillations. What is the period of the oscillation given that the moment of inertia about the pivot point is ml2/9? L/3 Pivot L С.М. 2L/3
A uniform rod of mass m- 9 kg has length L-70 cm. Instead of pivoting it at its end, we pivoted it at L/3 from the end as shown in the figure. We now set the rod into small angle oscillations. What is the period of the oscillation given that the moment of inertia about the pivot point is mL2/9? L/3 Pivot L с.м. 2L/3
A ball of mass M, moving with speed V, strikes the end of a motionless, uniform stick of mass Mand length L, fixed at pivot point P. After the collision, the stick is rotating about the pivot point P as shown, and the ball rebounds with speed V/3. The moment of inertia of the stick about Pis (ML2/3. The angular speed w of the stick is: Initial P Final L M MV VV O 4V/L OV/L O2V/L OV
5. 0/1 points Previous Answers SerPSE10 15.5.OP.025. My Notes A meter stick is attached to one end of a rigid rod with negligible mass of length = 0.502 m. The other end of the light rod is suspended from a pivot point, as shown in the figure below. The entire system is pulled to a small angle and released from rest. It then begins to oscillate. (a) What is the period of oscillation of the system (in s)? (Round your...
A pendulum is made of a rod of mass 4.9 kg and length 4.1 m whose moment of inertia about its center of mass is ML2 and a thin cylindrical disk of mass 2.4 kg and ra- dius 1.7 m whose moment of inertia about its center of mass is MR2. 4.1 m 4.9 kg - 1.7 m 2.4 kg What is the moment of inertia of the pen- dulum about the pivot point? Answer in units of kg. m².
Pivoted Rod with Unequal Masses (Figure 1) A thin rod of mass mr and length 2L is allowed to pivot freely about its center, as shown in the diagram. A small sphere of mass m1 is attached to the left end of the rod, and a small sphere of mass m2 is attached to the right end. The spheres are small enough that they can be considered point particles. The gravitational force acts downward, with the magnitude of the gravitational acceleration...
L- Pivot Point 13.) A uniform, thin rod of length L and mass M is allowed to pivot about its end, as shown in the figure above (a) Using integral calculus, derive the rotational inertia for the rod around its end to show that it is ML2/3 The rod is fixed at one end and allowed to fall from the horizontal position A through the vertical position B. (b) Derive an expression for the velocity of the free end of...
(Figure 1)The figure shows a simple model of a seesaw These consist of a plank/rod of mass mr and length 2x allowed to pivot freely about its center (or central axis), as shown in the diagram. A small sphere of mass m1 is attached to the left end of the rod, and a small sphere of mass m2 is attached to the right end. The spheres are small enough that they can be considered point particles. The gravitational force acts...
Q20 (15 points): A bullet of mass m X102 kg is moving with a speed of 100 m/s when it collides with a rod of mass mR 5 kg and length L m (shown in the figure). The rod is initially at rest, in a vertical position, and pivots about an axis going through its center of mass. The bullet imbeds itself in the rod at a distance L/4 from the pivot point. As a result, the bullet-rod system starts...