As per the information provided in the question the engineer want to make a choice between two alternatives as deep cut or lift station to run sanitary sewer
Deep Cut Alternative
Cost of pipe (I) = $50000
Annual Operation and maintenance cost (A) =$ 500 per year
Useful life (N) = 40 years
Interest rate (i) = 7%
Present worth (PW) of cost = 50000 + 500(P/A,7%,40) =50000 + 500(13.3317) = 50000 + 6665.85
Present worth (PW) of cost =$56665.85 (Lowest Cost)
Lift station Alternative
Cost of lift station (I) = $25000
Annual Operation and maintenance cost (A) =$ 2000 per year
Useful life (N) = 20 years
Interest rate (i) = 7%
Though the lifecycle of both the alternative (deep cut or lift station) are not equal, we need to use lowest common multiple (LCM) method of lifecycle of alternative, to convert the unequal lifecycle to equal lifecycle. Accordingly to estimate the present worth (PW) of cost the effective Life cycle of Lift station Alternative has to repeat 2 times
Present worth (PW) of cost = 25000 + 25000(P/F,7%,20) + 2000(P/A,7%,40)
Present worth (PW) of cost = 25000 + 25000(0.2584) + 2000(13.3317)
Present worth (PW) of cost = 25000 + 6460 + 26663.4
Present worth (PW) of cost = $58123.4
Among two alternatives, the engineer should select Deep Cut Alternative to run sanitary sewer for its least cost or cost effectiveness.
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