I need help solving these. I need to know the steps and calculations.
1) No of mol of compound (n)= weight / molecular
weight
weight of K2S = 2.7 g
molecular weight of K2S = 110.3 g/mol
n = 2.7/110.3 = 0.0245 mol
2) mass of K2S = 4.26 G
3) no of atoms of Cu = n*N0 ( 1 mole = N0 = 6.023*10^23 atoms)
= 7.1*6.023*10^23
= 4.28*10^24 atoms
4) No of mole of C atoms = no of atoms/N0
= (5.8*10^21)/(6.023*10^23)
= 9.63*10^-3 mol
5) No of mole of Fe atoms = w/m.wt = 81.4/56 = 1.45 mol
No of atoms of Fe = 1.45*6.023*10^23 = 8.735*10^23 atoms
6) Mass of Ar atoms = (no of atoms/No)*atomic mass of Ar
= ((9.3*10^24)/(6.023*10^23))*40
= 617.63 g
7) 1 mol Ag2Cr2O7 = 2 mol Ag
no of mol of Ag present = 2.65 mol
Mass of Ag present = n*At.wt
= 2.65*108
= 286.2 g
I need help solving these. I need to know the steps and calculations. 1. (1 pt)...
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