Question

Answer the questions below about the highlighted atom in this Lewis structure: 

In how many sigma bonds does the highlighted atom participate? 

In how many pi bonds does the highlighted atom participate? 

What is the orbital hybridization of the highlighted atom?

Answer 1

Q.1) In how many sigma bonds does the highlighted atom participate ?

ANSWER : 2

Highlighted carbon atom forms one sigma bond with neighboring Carbon & one with neighboring Nitrogen atom.

Q.2 ) In how many pi bonds does the highlighted atom participate ?

ANSWER : 2

Highlighted Carbon atom forms two pi bonds with N atom.

Q.3 ) What is the orbital hybridization of the highlighted atom ?

ANSWER : SP

Consider excited state electronic configuration of Carbon atom.

₆ C ^* 1 s ² , 2 s ¹ , 2 p x ¹ , 2 p y ¹ , 2 p z ¹

2 s & 2 p orbital of Carbon atom undergoes SP hybridization and forms two SP hybrid orbitals. These orbitals are used for making two sigma bonds with Carbon & Nitrogen atom.

Rest two half filled atomic orbitals of C namely 2 p y and 2 p z makes two pi bond with half filled p orbitals of  N atom.