Question

Answer the questions below about the highlighted atom in this Lewis structure: H-C-C=C-H H In how many sigma bonds does the highlighted atom participate? In how many pi bonds does the highlighted atom participate? X 5 ? What is the orbital hybridization of the highlighted atom?

Answer 1

-ċ-CECH Propyne. A sigma Bond is a covalent bond which is Formed by head on overlap of two atomic orbitals. A pi Bond is covalent bond which is formed by side-to-side overlap of two a to mic orbitals. the highlighted a] In how many sigma bonds does atom participate ? Hobond. I 6 bond H¢+EETH Gbond Ĥ o bond. &bond Ebond. whenever there is a single bond formed beth two atoms, is always Sigma bondo, triple bond means 16 and 27 bonds. In carbon ①, there is a sigma bonds [3 with C-H and one with c-c] and at no π bonds.

veya In overall structure, there are six sigma bonds and at bonds are present, as shown in above Structure. bonds 2IT bonds. 6 bond Labond HI obond H obond o bond sbond . Í propune of highlighted c] what is orbital hybridization atom ? H- och a = 8-H Propyne Á SP sp. the carbon in methyl group attached to CH3CECH has to form four sigma csingle) Bonds, three with 3-H and one with c-c. Its in sp3 in hybridized state as it has to provide four equivalent orbitals for sharing. the Bond angle is logºs'. In 6 and ③ carbon they are sp hybridized.