Question

Suppose the longths of the pregnancies of a certain animal are approximately normally distributed with mean 184 days and standard deviation 16 days. Complete parts(a) through) below. a) What is the probability that a randomly selected pregnancy tests less than 179 days? The probability that a randomly selected pregnancy lasts less than 179 days is approximately (Round to four decimal places as needed.) Interpret this probability Select the correct choice below and Round to the nearest Integer needed) in the answer box within your choice O A 100 pregnant individuals were selected independently from this population, we would expect 100 pregnant individuals were selected independently from this population, we would expect pregnancies to last exactly 179 days pregnancies to last more than 179 days OB O f 100 pregnant individuals were selected independently from this population, we would expect pregnancies to last less than 179 days b) Suppose a random sample of 18 pregnancies is obtained. Describe the sampling distribution of the sample mean length of pregnancies The sampling dibution of is (Round to our decimal places as needed) c) What is the probability that a random sample of 18 pregnancies has a mean gestation period of 179 days or loss? The probability that the mean of a random sample of 18 pregnancies loss than 179 days in aproximately Round to four decimal places as needed) Interpret the probability Select the correct choice below and fill in the answer box within your choice (Round to the nearest Integer as needed A 100 independent random samples of sien 18 pregnancies were obtained from this population, we would expect samples) to have a sample mean of 179 days or less OB 100 indecendent random samples of size 18 pregnancies were obtained from this population we would expect samples to have a sample mean of exactly 179 days OC I 100 independent and samples of sona 18 pregnancies were obtained from this population we would expect samples) to have a sample mean of 179 days or more Click to select your answers)

Answer 1

Ans: Mean (M = 100, Sta devlo) = 16 xoNL184, 16) ..). ? (xc 179) = (x 2 179 - 124) p/2C-0.31) = 0.37928 = (0.3823 -) If 100 pregnant endoriduals were selected independently from the population we would expect (38) pregrancres to list less than 179 days the b) n = 18, x = e = 184, 07 / The Sampling distribution of x 25 normal with che = 1184 and Oz - [ 3.7712 10 I (xz 179) = P(x-Mac 179-184) = P (26-1.33) = (0.0918] -) If 100 Andividual dass random samples of size n=18 Peregnancies were obtain from the population, we would expect (9) to have sample mean of 179 days or less 3.7712

das d) n = 67, V ol x-24 179-184) p/ x<191) = Plan 7 - 012<-2.56) = 0.0052 -) If 100 Independent vandom samples of size 67 obfewned, we would expect I to have sample mean of 179 days & less.