Question

A hollow aluminum cylinder 17.0 cm deep has an internal capacity of 2.000 L at 23.0°C. It is completely filled with turpentine at 23.0°C. The turpentine and the aluminum cylinder are then slowly warmed together to 75.0*C. (The average linear expansion coefficient for aluminum is 24 x 10-5*C, and the average volume expansion coefficient for turpentine is 9.0 x 10-**-*) (a) How much turpentine overflows? -655x The response you submitted as the wrong sign. cm (b) What is the volume of turpentine remaining in the cylinder at 25.0°C? (Give your answer to four significant figures.) 1000 X Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff errorem (c) If the combination with this amount of turpentine is then cooled back to 23.0°C, how far below the cylinder's rim does the turpentine's surface recede? Need Help? Tote Tier

Answer 1

alven data; Liolume = 2L length = 17cm a) we know that All= (3-3 dae kat 2 97104_3(214105) x2000cm? x 52°C AV = 86.11 cm b) let us consider, VE = VAI (1+30 ha) = 2000 (1+3 (2.47105)*52 = 21007488 L VE – 2007.48 cm3 c) we know that, V=2007148 (1+9x109 (-52°c) - 191315375 cm s 2000cm3-1913.5375CM - - 2000cm3 =) 4.32 % Now, 4.32X*.170m TOO = 0.6048 om