A hollow aluminum cylinder 16.5 cm deep has an internal capacity of 2.000 L at 16.0°C....
A hollow aluminum cylinder 16.5 cm deep has an internal capacity of 2.000 L at 16.0°C. It is completely filled with turpentine at 16.0°C. The turpentine and the aluminum cylinder are then slowly warmed together to 70.0°C. (The average linear expansion coefficient for aluminum is 24 ✕ 10−6°C−1, and the average volume expansion coefficient for turpentine is 9.0 ✕ 10−4°C−1.)
(b) What is the volume of turpentine remaining in the cylinder
at 70.0°C? (Give your answer to at least four significant
figures.)
Homework Answers
Area, A = 0.002/0.165 = 0.012 m^2
Volume of overflown liquid,
dV = 2 (0.0009 - (3 x 24 x 10^-6)) x (70 - 16) = 0.0894 L
Volume of turpentine, V = 2 - 0.0894 = 1.91 L
Comment in case any doubt please rate my answer....
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