as the curve is uniform, so acceleration of the curve is given by
a = ( 0 - 20) / ( 20-0) = - 1 m/s^2
now applying 2nd equation of motion
v^2 = u^2 + 2 a d
10^2 = 20^2 - 2 * 1*d
d = 150 m
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b)
displacement = area under v-t curve
d = 0.5* 20* 20 + (-10)*10
d = 100 m
=======
c)
a = - 1 m/s^2
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do comment in case any doubt, will reply for sure . Goodluck
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