Given,
m = 50 kg ; theta = 30 deg ; D = 105 m ; v = 1/2 m/s ; x = 5 m;
a)Since no friction,
a = g sin(theta)
a = 9.8 sin30 = 4.9 m/s^2
a = 4.9 m/s^2
b)P = m v
P = 0
Hence, P = 0
c)s = ut + 1/2 at^2
s = 105 - 5 = 100
t = sqrt (2 x 100/4.9) = 6.4 s
Hence, t = 6.4 s
d)v = u + at
v = 0 + 4.9 x 6.4 = 31.36 m/s
Hence, v = 31.36 m/s
e)P' = 0
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