Homework Answers
1)The reaction is an acid-base reaction.
2)The acid is HCl and base is the carbonate ion(of CaCO3).
The reactant that is acting as base is CO3-2
3) %mass
From the stoichiometric eqution
2 mole Hcl react with 1 mol of carbonate
so
375.0mL x 0.150M /2 = mmol of Carbonate
=28.125 mmol
mass of CaCO3 in sample = mol x molar mass
=28.125x10-3 mol x100g/mol
= 2.8125 g
% percent = mass of CACO3 x100/ mass of sample
=2.8125gx100/3.20g
= 87.89%
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