A parallel-plate capacitor has circular plates of 8.40 cm radius and 1.50 mm separation.
(a) Calculate the capacitance.
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(b) What charge will appear on the plates if a potential difference of 118 V is applied?
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A parallel-plate capacitor has circular plates of 8.40 cm radius and 1.50 mm separation. (a) Calculate...
A parallel-plate capacitor has circular plates of 7.67 cm radius and 1.52 mm separation. (a) Calculate the capacitance. (b) What charge will appear on the plates if a potential difference of 137 V is applied?
A parallel-plate capacitor has circular plates of 11.5 cm radius and 1.73 mm separation. (a) Calculate the capacitance. (b) What charge will appear on the plates if a potential difference of 175 V is applied?
A parallel plate capacitor is constructed with circular plates of radius 0.750 cm and plate separation 0.0500 mm. If the capacitor is connected across a 37.2 V source, find: a) the capacitance b) the surface charge on each plate c) The energy stored in the capacitor d) the electric field between the plates e) the energy density between the plates
3. A parallel-plate capacitor has capacitance C -8.40 pF. The separation between the plates is 1.30 mm. If the electric field in the region between the plates is 1.5x104 V/m, the magnitude of charge that can be placed on each plate is 164 pc O 560 pc 210 pc O 82 pc O 328 pc
Suppose that a parallel-plate capacitor has circular plates with radius R = 23 mm and a plate separation of 3.8 mm. Suppose also that a sinusoidal potential difference with a maximum value of 110 V and a frequency of 85 Hz is applied across the plates; that is, V = (110 V) sin[2π(85 Hz)t]. Find Bmax(R), the maximum value of the induced magnetic field that occurs at r = R.
Suppose that a parallel-plate capacitor has circular plates with radius R = 26 mm and a plate separation of 4.1 mm. Suppose also that a sinusoidal potential difference with a maximum value of 170 V and a frequency of 82 Hz is applied across the plates; that is, V = (170 V) sin[2π(82 Hz)t]. Find Bmax(R), the maximum value of the induced magnetic field that occurs at r = R.
Suppose that a parallel-plate capacitor has circular plates with radius R = 32 mm and a plate separation of 4.7 mm. suppose also that a sinusoidal potential difference with a maximum value of 160 V and a frequency of 60 Hz is applied across the plates: that is, V = (160 V) sin[2 n(60 Hz)t] Find B_max, the maximum value of the induced magnetic that occurs at r = R.
Suppose that a parallel-plate capacitor has circular plates with radius R = 37 mm and a plate separation of 6.8 mm. Suppose also that a sinusoidal potential difference with a maximum value of 120 V and a frequency of 47 Hz is applied across the plates; that is, V = (120 V) sin[2π(47 Hz)t]. Find Bmax(R), the maximum value of the induced magnetic field that occurs at r = R.
A parallel plate capacitor with circular plates of radius R = 16.0 cm and plate separation d = 9.00 mm is being charged at the rate of 8.00 C/s. What is the displacement current through a circular loop of radius r = 21.00 cm centered on the axis of the capacitor? 8.00 You are correct. What is the displacement current through a circular loop of radius r = 3.00 cm centered on the axis of the capacitor? What is the...
A parallel-plate capacitor has a plate separation of 2.30 mm. If the material between the plates is air, what plate area A is required to provide a capacitance of 1.50 pF? A : m2