Question

b) Sketch all possible geometrical isomers and then indicate which of these complexes would exhibit optica activity. Also identify each complex by name a) [Fe(C,0.).cllion (C.0, oxalate ion), b) [PdCI,(PP) Q4. Assigne the point group of the following compounds (show all your work)

Answer 1

Dear Student, Kindly refer to the complete solution. Feel free to ask if you face difficulty in understanding any step of the solution attached so that we can assist you in a better way.

Dear student, @ [fechou) at ion name: dichlarido bisoxalatdiron (oxidation state) * charge on the complexion is not visible and the charge is not possible as Pe cannot have tz oxidation. Thus, you can calculate oxidation state of fe in following way! het onêdation state of fe be a Solce x + 21-2) + 21-1)= charge on complex x-4-2= charge on complex x-6= charge on complex Geometrical isomers in charge 9-&- -Co O = cis-form 0 Coptically active) Its mivese image is on R.r.o.

ce & charge - - 9-d- - O U=0 Transform is optically inactive charge u- 9-8-9 -c=0 . [PdCG (PPh ] Name: dichloridobis (teiphenylphosphine) palladium (II) het bridation state of Pd bex x + 2(-1) + 2(0) = 0 x-2=0 Ta=+2] P.T.O.

Geometrical isomers: - Pole peb is form Transform shey do not show optical isomerism because of presence of plane of symmetry. Best wishes)