12)
Molar mass of K = 39.1 g/mol
mass(K)= 0.2 g
use:
number of mol of K,
n = mass of K/molar mass of K
=(0.2 g)/(39.1 g/mol)
= 5.115*10^-3 mol
Molar mass of H2O,
MM = 2*MM(H) + 1*MM(O)
= 2*1.008 + 1*16.0
= 18.016 g/mol
mass(H2O)= 15.0 g
use:
number of mol of H2O,
n = mass of H2O/molar mass of H2O
=(15 g)/(18.02 g/mol)
= 0.8326 mol
Balanced chemical equation is:
2 K + H2O ---> 2 KOH + H2
2 mol of K reacts with 1 mol of H2O
for 5.115*10^-3 mol of K, 2.558*10^-3 mol of H2O is required
But we have 0.8326 mol of H2O
so, K is limiting reagent
we will use K in further calculation
Molar mass of KOH,
MM = 1*MM(K) + 1*MM(O) + 1*MM(H)
= 1*39.1 + 1*16.0 + 1*1.008
= 56.108 g/mol
According to balanced equation
mol of KOH formed = (2/2)* moles of K
= (2/2)*5.115*10^-3
= 5.115*10^-3 mol
use:
mass of KOH = number of mol * molar mass
= 5.115*10^-3*56.11
= 0.287 g
Answer: 0.287 g
Only 1 question at a time please
12. Potassium reacts aggressively with water, as shown in this equation: 2 K + 2 H20→2...
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